What is the solution for x((dy)/(dx))=y+xe^{y/x} ?

The solution for x((dy)/(dx))=y+xe^{y/x} is y=-xln(-ln(x)-c_{1})

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x((dy)/(dx))=y+xe^{y/x}

x (\frac{d y}{d x}) = y + x e^{\frac{y}{x}}

y = - x ln (- ln (x) - c_{1})

Solution steps

x (\frac{d y}{d x}) = y + x e^{\frac{y}{x}}

Solve using substitution:

y = - x ln (- ln (x) - c_{1})

y = - x ln (- ln (x) - c_{1})

y = \frac{2}{1 + x ^{2}}, y = 1

f (x) = 3 x + 1

\frac{\partial}{\partial x} (10)

\frac{\partial}{\partial y} (x^{2} + 2 y^{2} + 3 x z)

x \to - 2 lim (\frac{1}{x + 1})

What is the solution for x((dy)/(dx))=y+xe^{y/x} ?
The solution for x((dy)/(dx))=y+xe^{y/x} is y=-xln(-ln(x)-c_{1})