What is the derivative of y=(3x+1)^2 ?

The derivative of y=(3x+1)^2 is 6(3x+1)

What is the first derivative of y=(3x+1)^2 ?

The first derivative of y=(3x+1)^2 is 6(3x+1)

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derivative of

y = (3 x + 1)^{2}

6 (3 x + 1)

Solution steps

\frac{d}{d x} ((3 x + 1)^{2})

Apply the chain rule:

2 (3 x + 1) \frac{d}{d x} (3 x + 1)

= 2 (3 x + 1) \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= 2 (3 x + 1) \cdot 3

Simplify

= 6 (3 x + 1)

\frac{d}{d x} (- y + x + 2)

\int \frac{sec ^{2} ( x )}{2 x} d x

(x - 1) \cdot ln (x - 1)

x \to 0 lim (\frac{x ^{3} + 3 x}{x})

\int tan^{3} (θ) sec^{2} (θ) d θ

What is the derivative of y=(3x+1)^2 ?
The derivative of y=(3x+1)^2 is 6(3x+1)
What is the first derivative of y=(3x+1)^2 ?
The first derivative of y=(3x+1)^2 is 6(3x+1)