What is the first d/(dt)(1+t^3) ?

The first d/(dt)(1+t^3) is 3t^2

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d/(dt)(1+t^3)

\frac{d}{d t} (1 + t^{3})

3 t^{2}

Solution steps

\frac{d}{d t} (1 + t^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) + \frac{d}{d t} (t^{3})

\frac{d}{d t} (1) = 0

\frac{d}{d t} (t^{3}) = 3 t^{2}

= 0 + 3 t^{2}

Simplify

= 3 t^{2}

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