What is the integral of 4/(sqrt(t)) ?

The integral of 4/(sqrt(t)) is 8sqrt(t)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 4/(sqrt(t))

\int \frac{4}{t} d t

8 t + C

Solution steps

\int \frac{4}{t} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{t} d t

Apply the Power Rule

: 2 t^{\frac{1}{2}}

= 4 \cdot 2 t^{\frac{1}{2}}

Simplify

4 \cdot 2 t^{\frac{1}{2}} : 8 t

= 8 t

Add a constant to the solution

= 8 t + C

\frac{\partial}{\partial x} (2 x y)

f (g (x))

\frac{\partial}{\partial x} (x^{y^{z}})

f (x) = 7 x + 1, at x = 5

2 sin (2 x - π), 5 sin (2 x - 3 π)