What is area 2sin(2x-pi),5sin(2x-3pi) ?

The answer to area 2sin(2x-pi),5sin(2x-3pi) is 3

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area 2sin(2x-pi),5sin(2x-3pi)

area

2 sin (2 x - π), 5 sin (2 x - 3 π)

3

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{2}} ∣ 2 sin (2 x - π) - 5 sin (2 x - 3 π) ∣ d x

Solve

\int_{0}^{\frac{π}{2}} ∣ 2 sin (2 x - π) - 5 sin (2 x - 3 π) ∣ d x : 3

The area is:

= 3

\int \frac{1}{( 5 + x ) ^{2}} d x

\frac{d}{d x} (\frac{x ^{2}}{( x - 1 )})

\int x^{2} + 6 e^{x} + C d x

\int e x d x

\int \frac{sin ( 2 x )}{1 - sin ^{2} ( x )} d x

What is area 2sin(2x-pi),5sin(2x-3pi) ?
The answer to area 2sin(2x-pi),5sin(2x-3pi) is 3