What is the solution for xy^'-y=(x^2)/(y^2) ?

The solution for xy^'-y=(x^2)/(y^2) is y=-\sqrt[3]{x^2}\sqrt[3]{3-c_{1}x}

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xy^'-y=(x^2)/(y^2)

x y^{^{'}} - y = \frac{x ^{2}}{y ^{2}}

y = - 3 x^{2} 3 3 - c_{1} x

Solution steps

x y^{'} (x) - y = \frac{x ^{2}}{y ^{2}}

Solve Bernoulli ODE:

y = - 3 x^{2} 3 3 - c_{1} x

y = - 3 x^{2} 3 3 - c_{1} x

\frac{d ^{2}}{d x ^{2}} (\frac{2}{4 x + 3})

25

4 - x^{2}, 3 x

\int (3 x^{2} - 2 x + 1) d x

\int \frac{x ^{2} - 1}{x} d x

What is the solution for xy^'-y=(x^2)/(y^2) ?
The solution for xy^'-y=(x^2)/(y^2) is y=-\sqrt[3]{x^2}\sqrt[3]{3-c_{1}x}