What is (\partial)/(\partial x)(e^{2xyz-1}) ?

The answer to (\partial)/(\partial x)(e^{2xyz-1}) is e^{2xyz-1}*2yz

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(\partial)/(\partial x)(e^{2xyz-1})

\frac{\partial}{\partial x} (e^{2 x yz - 1})

e^{2 x yz - 1} \cdot 2 yz

Solution steps

\frac{\partial}{\partial x} (e^{2 x yz - 1})

Treat

y, z

as constants

Apply the chain rule:

e^{2 x yz - 1} \frac{\partial}{\partial x} (2 x yz - 1)

= e^{2 x yz - 1} \frac{\partial}{\partial x} (2 x yz - 1)

\frac{\partial}{\partial x} (2 x yz - 1) = 2 yz

= e^{2 x yz - 1} \cdot 2 yz

\frac{d}{d x} (e^{2 x} + 4)

\int_{0}^{4} (x + 3 x) d x

\int e^{x} e^{x} + 5 d x

\frac{d y}{d x} = (x + y)^{2}

f (x) = \frac{1}{2 x}, at x = 9

What is (\partial)/(\partial x)(e^{2xyz-1}) ?
The answer to (\partial)/(\partial x)(e^{2xyz-1}) is e^{2xyz-1}*2yz