What is the tangent of f(x)=3x^2+5x,\at x=-2 ?

The tangent of f(x)=3x^2+5x,\at x=-2 is y=-7x-12

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tangent of f(x)=3x^2+5x,\at x=-2

tangent of

f (x) = 3 x^{2} + 5 x, at x = - 2

y = - 7 x - 12

Solution steps

Find the tangent point:

(- 2, 2)

Find the slope of

f (x) = 3 x^{2} + 5 x : \frac{df ( x )}{d x} = 6 x + 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 7

Find the line with slope m=

- 7

and passing through

(- 2, 2) : y = - 7 x - 12

y = - 7 x - 12

x \to \frac{π}{2} lim (\frac{x}{cos ( x )})

\frac{d y}{d x}, x + 4 y = 1

y^{^{''}} + 7 y^{^{'}} + 12 y = 0, y (0) = 1, y^{^{'}} (0) = 0

\int 18 sin^{3} (x co) s^{2} x

\int_{1}^{5} 8 x d x

What is the tangent of f(x)=3x^2+5x,\at x=-2 ?
The tangent of f(x)=3x^2+5x,\at x=-2 is y=-7x-12