What is the derivative of 6x^2+4x ?

The derivative of 6x^2+4x is 12x+4

What is the first derivative of 6x^2+4x ?

The first derivative of 6x^2+4x is 12x+4

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\frac{d}{d x} (6 x^{2} + 4 x)

12 x + 4

Solution steps

\frac{d}{d x} (6 x^{2} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (4 x) = 4

= 12 x + 4

f (x) = \frac{66}{( 1 - x ) ^{4}}

g (x) = sin (π) - 2

\frac{d x}{d t} = 5 \cdot 0.00001 - \frac{5 x}{10000}, x (0) = 2

\int 3 + 9 x^{2} d x

\int \frac{4}{sin ^{2} ( 2 x )} d x

What is the derivative of 6x^2+4x ?
The derivative of 6x^2+4x is 12x+4
What is the first derivative of 6x^2+4x ?
The first derivative of 6x^2+4x is 12x+4