What is the derivative of y=sin(sin(x)) ?

The derivative of y=sin(sin(x)) is cos(sin(x))cos(x)

What is the first derivative of y=sin(sin(x)) ?

The first derivative of y=sin(sin(x)) is cos(sin(x))cos(x)

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derivative of

y = sin (sin (x))

cos (sin (x)) cos (x)

Solution steps

\frac{d}{d x} (sin (sin (x)))

Apply the chain rule:

cos (sin (x)) \frac{d}{d x} (sin (x))

= cos (sin (x)) \frac{d}{d x} (sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

= cos (sin (x)) cos (x)

y^{^{''}} = - 4 y

\int_{0}^{1} \frac{3}{2 t - 5} d t

\int_{1}^{4} x^{2} - 4 x - 3 d x

\int_{- \infty}^{4} x e^{x} d x

\frac{3}{s ^{2} + 3 s + 6}

What is the derivative of y=sin(sin(x)) ?
The derivative of y=sin(sin(x)) is cos(sin(x))cos(x)
What is the first derivative of y=sin(sin(x)) ?
The first derivative of y=sin(sin(x)) is cos(sin(x))cos(x)