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Popular >

y^'=7xe^y

Solution

y^{^{'}} = 7 x e^{y}

Solution

y = - ln (- \frac{7 x ^{2}}{2} - c_{1})

Solution steps

y^{'} (x) = 7 x e^{y}

Solve separable ODE:

y = - ln (- \frac{7 x ^{2}}{2} - c_{1})

y = - ln (- \frac{7 x ^{2}}{2} - c_{1})

Graph

Popular Examples

(1+x^2)y+xy^'+ax=0

(1 + x^{2}) y + x y^{^{'}} + a x = 0

limit as k approaches 0 of (x^2k+3xk^2+k^3)/(2xk+5k^2)

k \to 0 lim (\frac{x ^{2} k + 3 x k ^{2} + k ^{3}}{2 x k + 5 k ^{2}})

derivative of (1+x/(1+e^x))

\frac{d}{d x} (\frac{1 + x}{1 + e ^{x}})

x^2y^{''}+9xy^'+16y=0

x^{2} y^{^{''}} + 9 x y^{^{'}} + 16 y = 0

f (x) = sin (5 x)

Frequently Asked Questions (FAQ)

What is the solution for y^'=7xe^y ?
The solution for y^'=7xe^y is y=-ln(-(7x^2)/2-c_{1})