What is v'=(8*9.8+3.1v^2)/8 ?

The answer to v'=(8*9.8+3.1v^2)/8 is v=sqrt((6.32258E15)/(2.5E14))i,v=-sqrt((6.32258E15)/(2.5E14))i

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v'=(8*9.8+3.1v^2)/8

v^{'} = \frac{8 \cdot 9.8 + 3.1 v ^{2}}{8}

v = \frac{6.32258 E 15}{2.5 E 14} i, v = - \frac{6.32258 E 15}{2.5 E 14} i

Solution steps

v^{'} = \frac{8 \cdot 9.8 + 3.1 v ^{2}}{8}

v^{'} = 0

0 = \frac{8 \cdot 9.8 + 3.1 v ^{2}}{8}

0 = \frac{8 \cdot 9.8 + 3.1 v ^{2}}{8} : v = \frac{6.32258 E 15}{2.5 E 14} i, v = - \frac{6.32258 E 15}{2.5 E 14} i

v = \frac{6.32258 E 15}{2.5 E 14} i, v = - \frac{6.32258 E 15}{2.5 E 14} i

x \to 3 lim (\frac{x ^{2} + 1}{10})

y^{^{''}} - 5 y^{^{'}} = 8 t

y^{^{'}} = y, y (0) = 1

\int \frac{( 2 x + 1 )}{x ^{2} - 1} d x

2 e^{x} (cos (x) - sin (x))

What is v'=(8*9.8+3.1v^2)/8 ?
The answer to v'=(8*9.8+3.1v^2)/8 is v=sqrt((6.32258E15)/(2.5E14))i,v=-sqrt((6.32258E15)/(2.5E14))i