What is (\partial)/(\partial y)(2xy-sec^2(x)) ?

The answer to (\partial)/(\partial y)(2xy-sec^2(x)) is 2x

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(\partial)/(\partial y)(2xy-sec^2(x))

\frac{\partial}{\partial y} (2 x y - sec^{2} (x))

2 x

Solution steps

\frac{\partial}{\partial y} (2 x y - sec^{2} (x))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x y) - \frac{\partial}{\partial y} (sec^{2} (x))

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (sec^{2} (x)) = 0

= 2 x - 0

Simplify

= 2 x

- 2

2 x^{2} + x

\int x^{2} - \frac{1}{x ^{2}} d x

\int z d z

\frac{d}{d x} ((x + 4)^{\frac{2}{3}} (2 x^{2} - 1)^{3})

What is (\partial)/(\partial y)(2xy-sec^2(x)) ?
The answer to (\partial)/(\partial y)(2xy-sec^2(x)) is 2x