What is the solution for (x^2+1)(dy)/(dx)+5x(y-1)=0,y(0)=4 ?

The solution for (x^2+1)(dy)/(dx)+5x(y-1)=0,y(0)=4 is y= 3/((x^2+1)^{5/2)}+1

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(x^2+1)(dy)/(dx)+5x(y-1)=0,y(0)=4

(x^{2} + 1) \frac{d y}{d x} + 5 x (y - 1) = 0, y (0) = 4

y = \frac{3}{( x ^{2} + 1 ) ^{\frac{5}{2}}} + 1

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 5 x (y - 1) = 0

Solve separable ODE:

y = \frac{3}{( x ^{2} + 1 ) ^{\frac{5}{2}}} + 1

y = \frac{3}{( x ^{2} + 1 ) ^{\frac{5}{2}}} + 1

\int \frac{sin ( 2 x )}{1 + cos ^{2} ( x )} d x

\frac{d}{d x} (4 x^{3} - x)

\frac{d}{d x} ((x^{\frac{2}{3}} + 3) (x^{\frac{1}{3}} + 5 x))

\frac{d y}{d x} = \frac{sec ( y )}{( x + 5 ) ^{2}}

\int \frac{1}{x ^{2} x ^{2} - 121} d x

What is the solution for (x^2+1)(dy)/(dx)+5x(y-1)=0,y(0)=4 ?
The solution for (x^2+1)(dy)/(dx)+5x(y-1)=0,y(0)=4 is y= 3/((x^2+1)^{5/2)}+1