What is the integral from-1 to 1 of (1+sqrt(1-x^2)) ?

The integral from-1 to 1 of (1+sqrt(1-x^2)) is 2+pi/2

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integral from-1 to 1 of (1+sqrt(1-x^2))

\int_{- 1}^{1} (1 + 1 - x^{2}) d x

2 + \frac{π}{2}

Decimal Notation

3.57079 \dots

Solution steps

\int_{- 1}^{1} 1 + 1 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 1 d x + \int_{- 1}^{1} 1 - x^{2} d x

\int_{- 1}^{1} 1 d x = 2

\int_{- 1}^{1} 1 - x^{2} d x = \frac{π}{2}

= 2 + \frac{π}{2}

t^{2} y^{^{''}} + 19 t y^{^{'}} + 162 y = 0

3 cos (2 u)

n = 2 \sum \infty \frac{1}{n ^{2} + n}

\frac{1}{s ^{2} - 3}

\frac{d}{d x} (- 3 e^{1 - 3 x})

What is the integral from-1 to 1 of (1+sqrt(1-x^2)) ?
The integral from-1 to 1 of (1+sqrt(1-x^2)) is 2+pi/2