What is the derivative of-3e^{1-3x} ?

The derivative of-3e^{1-3x} is 9e^{1-3x}

What is the first derivative of-3e^{1-3x} ?

The first derivative of-3e^{1-3x} is 9e^{1-3x}

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\frac{d}{d x} (- 3 e^{1 - 3 x})

9 e^{1 - 3 x}

Solution steps

\frac{d}{d x} (- 3 e^{1 - 3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (e^{1 - 3 x})

Apply the chain rule:

e^{1 - 3 x} \frac{d}{d x} (1 - 3 x)

= e^{1 - 3 x} \frac{d}{d x} (1 - 3 x)

\frac{d}{d x} (1 - 3 x) = - 3

= - 3 e^{1 - 3 x} (- 3)

Simplify

= 9 e^{1 - 3 x}

\frac{d}{d x} (2 x + 4)

\frac{\partial}{\partial x} (\frac{( - y )}{x ^{2} + y ^{2}})

y^{^{''}} = a y

y^{^{'''}} - 4 y^{^{''}} - 5 y^{^{'}} = 0

x y = - 100

What is the derivative of-3e^{1-3x} ?
The derivative of-3e^{1-3x} is 9e^{1-3x}
What is the first derivative of-3e^{1-3x} ?
The first derivative of-3e^{1-3x} is 9e^{1-3x}