What is the derivative of sqrt(2x+4) ?

The derivative of sqrt(2x+4) is 1/(sqrt(2x+4))

What is the first derivative of sqrt(2x+4) ?

The first derivative of sqrt(2x+4) is 1/(sqrt(2x+4))

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\frac{d}{d x} (2 x + 4)

\frac{1}{2 x + 4}

Solution steps

\frac{d}{d x} (2 x + 4)

Apply the chain rule:

\frac{1}{2 2 x + 4} \frac{d}{d x} (2 x + 4)

= \frac{1}{2 2 x + 4} \frac{d}{d x} (2 x + 4)

\frac{d}{d x} (2 x + 4) = 2

= \frac{1}{2 2 x + 4} \cdot 2

Simplify

\frac{1}{2 2 x + 4} \cdot 2 : \frac{1}{2 x + 4}

= \frac{1}{2 x + 4}

\frac{\partial}{\partial x} (\frac{( - y )}{x ^{2} + y ^{2}})

y^{^{''}} = a y

y^{^{'''}} - 4 y^{^{''}} - 5 y^{^{'}} = 0

x y = - 100

\int 10 x \cdot x d x

What is the derivative of sqrt(2x+4) ?
The derivative of sqrt(2x+4) is 1/(sqrt(2x+4))
What is the first derivative of sqrt(2x+4) ?
The first derivative of sqrt(2x+4) is 1/(sqrt(2x+4))