What is the tangent of xy=-100 ?

The tangent of xy=-100 is y=(100)/(a_{0)^2}x-(200)/(a_{0)}

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tangent of xy=-100

tangent of

x y = - 100

y = \frac{100}{a _{0}^{2}} x - \frac{200}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - \frac{100}{a _{0}})

Find the slope of

x y = - 100 : \frac{d y}{d x} = \frac{100}{x ^{2}}

Compute the slope of

x y = - 100

x = a_{0} : m = \frac{100}{a _{0}^{2}}

Find the line with slope m=

\frac{100}{a _{0}^{2}}

and passing through

(a_{0}, - \frac{100}{a _{0}}) : y = \frac{100}{a _{0}^{2}} x - \frac{200}{a _{0}}

y = \frac{100}{a _{0}^{2}} x - \frac{200}{a _{0}}

\int 10 x \cdot x d x

f (x) = 3 x - 8

\int \frac{( x ^{2} + x + 1 )}{( x + 1 ) ^{2} ( x + 2 )} d x

y = a csc^{2} (k x)

What is the tangent of xy=-100 ?
The tangent of xy=-100 is y=(100)/(a_{0)^2}x-(200)/(a_{0)}