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Popular >

integral from-1 to 1 of (x^2+1)

Solution

\int_{- 1}^{1} (x^{2} + 1) d x

Solution

\frac{8}{3}

+1

Decimal Notation

2.66666 \dots

Solution steps

\int_{- 1}^{1} x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{2} d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} 1 d x = 2

= \frac{2}{3} + 2

Simplify

\frac{2}{3} + 2 : \frac{8}{3}

= \frac{8}{3}

Popular Examples

derivative of y=ln((e^x)/(e^x-1))derivative of

y = ln (\frac{e ^{x}}{e ^{x} - 1})

tangent of-4x^2-7x tangent of

- 4 x^{2} - 7 x

derivative of f(4)=10x-13 derivative of

f (4) = 10 x - 13

derivative of xe^{rx}

\frac{d}{d x} (x e^{r x})

x^2y^{''}+2xy^'-2y=0

x^{2} y^{^{''}} + 2 x y^{^{'}} - 2 y = 0

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (x^2+1) ?
The integral from-1 to 1 of (x^2+1) is 8/3