What is the solution for (1+x^2)(dy}{dx}=\frac{x^1)/y ?

The solution for (1+x^2)(dy}{dx}=\frac{x^1)/y is y=sqrt(ln(1+x^2)+c_{1)},y=-sqrt(ln(1+x^2)+c_{1)}

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(1+x^2)(dy}{dx}=\frac{x^1)/y

(1 + x^{2}) \frac{d y}{d x} = \frac{x ^{1}}{y}

y = ln (1 + x^{2}) + c_{1}, y = - ln (1 + x^{2}) + c_{1}

Solution steps

(1 + x^{2}) \frac{d y}{d x} = \frac{x ^{1}}{y}

Solve separable ODE:

y = ln (1 + x^{2}) + c_{1}, y = - ln (1 + x^{2}) + c_{1}

y = ln (1 + x^{2}) + c_{1}, y = - ln (1 + x^{2}) + c_{1}

\frac{d}{d x} (x^{4} - 13 x^{2} + 36)

∣ x ∣, 4 - x^{2}

sin (x), cos (x), \frac{3 π}{4}, \frac{7 π}{6}

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y^{^{'}} - \frac{5}{3} y = 1 - \frac{1}{5} t

What is the solution for (1+x^2)(dy}{dx}=\frac{x^1)/y ?
The solution for (1+x^2)(dy}{dx}=\frac{x^1)/y is y=sqrt(ln(1+x^2)+c_{1)},y=-sqrt(ln(1+x^2)+c_{1)}