What is the integral of 6x^{-1} ?

The integral of 6x^{-1} is 6ln|x|+C

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integral of 6x^{-1}

\int 6 x^{- 1} d x

6 ln ∣ x ∣ + C

Solution steps

\int 6 x^{- 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int x^{- 1} d x

Use the common integral:

\int x^{- 1} d x = ln (∣ x ∣)

= 6 ln ∣ x ∣

Add a constant to the solution

= 6 ln ∣ x ∣ + C

\int e^{2 + x} d x

\int sin (x) \cdot sin (n x) d x

(2 x - 1) d x + (5 y + 6) d y = 0

\frac{\partial}{\partial x} (x ln (\frac{x}{y}) + x y^{2})

\frac{c e ^{- a s}}{s ^{2}}