What is the derivative of 2e^{-3t} ?

The derivative of 2e^{-3t} is -6e^{-3t}

What is the first derivative of 2e^{-3t} ?

The first derivative of 2e^{-3t} is -6e^{-3t}

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derivative of

2 e^{- 3 t}

- 6 e^{- 3 t}

Solution steps

\frac{d}{d t} (2 e^{- 3 t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (e^{- 3 t})

Apply the chain rule:

e^{- 3 t} \frac{d}{d t} (- 3 t)

= e^{- 3 t} \frac{d}{d t} (- 3 t)

\frac{d}{d t} (- 3 t) = - 3

= 2 e^{- 3 t} (- 3)

Simplify

= - 6 e^{- 3 t}

\frac{11}{4} x^{2} d y - 14 d x = 0

\frac{d}{d x} ((x)^{7 x})

\int \frac{6 e ^{2 x}}{3 - e ^{4 x}} d x

\frac{4}{x ^{4}}

\frac{\partial}{\partial x} ((5 x + 6 y) - (x^{2} - 4 x y + 8 y^{2} + 7 x - 14 y - 6))

What is the derivative of 2e^{-3t} ?
The derivative of 2e^{-3t} is -6e^{-3t}
What is the first derivative of 2e^{-3t} ?
The first derivative of 2e^{-3t} is -6e^{-3t}