What is the derivative of g(t)=2t^{-1/4} ?

The derivative of g(t)=2t^{-1/4} is -1/(2t^{5/4)}

What is the first derivative of g(t)=2t^{-1/4} ?

The first derivative of g(t)=2t^{-1/4} is -1/(2t^{5/4)}

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derivative of

g (t) = 2 t^{- \frac{1}{4}}

- \frac{1}{2 t ^{\frac{5}{4}}}

Solution steps

\frac{d}{d t} (2 t^{- \frac{1}{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (t^{- \frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- \frac{1}{4} t^{- \frac{1}{4} - 1})

Simplify

2 (- \frac{1}{4} t^{- \frac{1}{4} - 1}) : - \frac{1}{2 t ^{\frac{5}{4}}}

= - \frac{1}{2 t ^{\frac{5}{4}}}

\int 2 sin (x) d x

\int \frac{2 + e ^{- x}}{x} d x

x \to 0 lim (\frac{x ^{4} + 6 x}{x})

x y^{^{'}} - y = x

(x \cdot sin (x))^{^{'}}

What is the derivative of g(t)=2t^{-1/4} ?
The derivative of g(t)=2t^{-1/4} is -1/(2t^{5/4)}
What is the first derivative of g(t)=2t^{-1/4} ?
The first derivative of g(t)=2t^{-1/4} is -1/(2t^{5/4)}