What is the tangent of f(x)= x/((3x-2)^6),\at x=1 ?

The tangent of f(x)= x/((3x-2)^6),\at x=1 is y=-17x+18

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tangent of f(x)= x/((3x-2)^6),\at x=1

tangent of

f (x) = \frac{x}{( 3 x - 2 ) ^{6}}, at x = 1

y = - 17 x + 18

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = \frac{x}{( 3 x - 2 ) ^{6}} : \frac{df ( x )}{d x} = \frac{- 2 - 15 x}{( 3 x - 2 ) ^{7}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 17

Find the line with slope m=

- 17

and passing through

(1, 1) : y = - 17 x + 18

y = - 17 x + 18

f (x) = (x - 1) x^{2} - 2 x + 2

\int x^{5} e^{x^{3} - 7} d x

n = 1 \sum \infty \frac{3}{4 n ^{2} - 1}

1 + cos (2 x)

\frac{\partial}{\partial x} (\frac{100 x}{( x + y ) ^{2}})

What is the tangent of f(x)= x/((3x-2)^6),\at x=1 ?
The tangent of f(x)= x/((3x-2)^6),\at x=1 is y=-17x+18