What is the derivative of sqrt(3+4x) ?

The derivative of sqrt(3+4x) is 2/(sqrt(3+4x))

What is the first derivative of sqrt(3+4x) ?

The first derivative of sqrt(3+4x) is 2/(sqrt(3+4x))

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\frac{d}{d x} (3 + 4 x)

\frac{2}{3 + 4 x}

Solution steps

\frac{d}{d x} (3 + 4 x)

Apply the chain rule:

\frac{1}{2 3 + 4 x} \frac{d}{d x} (3 + 4 x)

= \frac{1}{2 3 + 4 x} \frac{d}{d x} (3 + 4 x)

\frac{d}{d x} (3 + 4 x) = 4

= \frac{1}{2 3 + 4 x} \cdot 4

Simplify

\frac{1}{2 3 + 4 x} \cdot 4 : \frac{2}{3 + 4 x}

= \frac{2}{3 + 4 x}

\int \frac{- 30}{( 2 x + 1 ) ^{2}} d x

\int \frac{- sin ( x )}{cos ^{2} ( x )} d x

x \to 1 - lim (x^{2} + 1)

\int \frac{1}{7 - 5 x ^{2}} d x

\frac{1}{1 - x}, i

What is the derivative of sqrt(3+4x) ?
The derivative of sqrt(3+4x) is 2/(sqrt(3+4x))
What is the first derivative of sqrt(3+4x) ?
The first derivative of sqrt(3+4x) is 2/(sqrt(3+4x))