What is the integral of (-sin(x))/(cos^2(x)) ?

The integral of (-sin(x))/(cos^2(x)) is -sec(x)+C

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integral of (-sin(x))/(cos^2(x))

\int \frac{- sin ( x )}{cos ^{2} ( x )} d x

- sec (x) + C

Solution steps

\int \frac{- sin ( x )}{cos ^{2} ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{sin ( x )}{cos ^{2} ( x )} d x

Apply u-substitution

: \int - \frac{1}{u ^{2}} d u

= - \int - \frac{1}{u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int \frac{1}{u ^{2}} d u)

Apply the Power Rule

: - \frac{1}{u}

= - (- (- \frac{1}{u}))

Substitute back

u = cos (x)

= - (- (- \frac{1}{cos ( x )}))

Simplify

- (- (- \frac{1}{cos ( x )})) : - sec (x)

= - sec (x)

Add a constant to the solution

= - sec (x) + C

x \to 1 - lim (x^{2} + 1)

\int \frac{1}{7 - 5 x ^{2}} d x

\frac{1}{1 - x}, i

y = x^{3}, y = x^{2} - 4 x, [- 1, 1]

\int_{1}^{4} (7 x + x) d x

What is the integral of (-sin(x))/(cos^2(x)) ?
The integral of (-sin(x))/(cos^2(x)) is -sec(x)+C