What is the first d/(dn)(i^n) ?

The first d/(dn)(i^n) is i^nln(i)

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d/(dn)(i^n)

\frac{d}{d n} (i^{n})

i^{n} ln (i)

Solution steps

\frac{d}{d n} (i^{n})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= i^{n} ln (i)

x \to 1 lim (\frac{x ^{3}}{3})

f (x) = \frac{x}{5 + x}

f (x) = \frac{x}{x + 1}, at x = 4

2 s

2 x d y + (x^{2} y^{4} + 1) y d x = 0