What is the limit as x approaches 2 of sqrt(6x^2+1) ?

The limit as x approaches 2 of sqrt(6x^2+1) is 5

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limit as x approaches 2 of sqrt(6x^2+1)

x \to 2 lim (6 x^{2} + 1)

5

Solution steps

x \to 2 lim (6 x^{2} + 1)

Plug in the value

x = 2

= 6 \cdot 2^{2} + 1

Simplify

6 \cdot 2^{2} + 1 : 5

= 5

\int_{- \infty}^{0} e^{9 x} d x

t^{2} (\frac{d y}{d t}) + 4 t y - y^{3} = 0

x^{3} + y^{3} - 6 x y = 0, (\frac{4}{3}, \frac{8}{3})

\int_{2}^{5} 4 x^{3} d x

f (x) = \frac{1 - x ^{2}}{( 1 + x ^{2} ) ^{2}}

What is the limit as x approaches 2 of sqrt(6x^2+1) ?
The limit as x approaches 2 of sqrt(6x^2+1) is 5