What is the limit as x approaches 4 of 6/((x-4)^2) ?

The limit as x approaches 4 of 6/((x-4)^2) is infinity

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limit as x approaches 4 of 6/((x-4)^2)

x \to 4 lim (\frac{6}{( x - 4 ) ^{2}})

\infty

Solution steps

x \to 4 lim (\frac{6}{( x - 4 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 4 - lim (\frac{6}{( x - 4 ) ^{2}}) = \infty

x \to 4 + lim (\frac{6}{( x - 4 ) ^{2}}) = \infty

= \infty

\frac{d y}{d x} = x y + 3 x + 2 y + 6

(y^{2} + 3 x y) d x - 3 x^{2} d y = 0

1 + s

f (x) = 23 sin (x) + 2 cos (x)

\frac{d}{d x} (cosh (\frac{4 x ^{3}}{x - 2}))

What is the limit as x approaches 4 of 6/((x-4)^2) ?
The limit as x approaches 4 of 6/((x-4)^2) is infinity