What is the tangent of f(x)=tan(x),(pi/4 ,1) ?

The tangent of f(x)=tan(x),(pi/4 ,1) is y=2x+1-pi/2

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tangent of f(x)=tan(x),(pi/4 ,1)

tangent of

f (x) = tan (x), (\frac{π}{4}, 1)

y = 2 x + 1 - \frac{π}{2}

Solution steps

Find the slope of

f (x) = tan (x) : \frac{df ( x )}{d x} = sec^{2} (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(\frac{π}{4}, 1) : y = 2 x + 1 - \frac{π}{2}

y = 2 x + 1 - \frac{π}{2}

\int \frac{4}{x ^{2} + 2 x + 5} d x

y (1 + x^{2}) y^{^{'}} - x (8 + y^{2}) = 0

\frac{d}{d x} (\frac{6}{x} - \frac{8}{x})

a^{x}

\frac{d}{d x} (- cos (4 x))

What is the tangent of f(x)=tan(x),(pi/4 ,1) ?
The tangent of f(x)=tan(x),(pi/4 ,1) is y=2x+1-pi/2