What is the derivative of (x^2+6)^9 ?

The derivative of (x^2+6)^9 is 18x(x^2+6)^8

What is the first derivative of (x^2+6)^9 ?

The first derivative of (x^2+6)^9 is 18x(x^2+6)^8

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derivative of

(x^{2} + 6)^{9}

18 x (x^{2} + 6)^{8}

Solution steps

\frac{d}{d x} ((x^{2} + 6)^{9})

Apply the chain rule:

9 (x^{2} + 6)^{8} \frac{d}{d x} (x^{2} + 6)

= 9 (x^{2} + 6)^{8} \frac{d}{d x} (x^{2} + 6)

\frac{d}{d x} (x^{2} + 6) = 2 x

= 9 (x^{2} + 6)^{8} \cdot 2 x

Simplify

= 18 x (x^{2} + 6)^{8}

\frac{\partial}{\partial z} (- x y)

t y^{^{''}} + y^{^{'}} = 0

f (x) = 7 x - 4 x^{2}, (- 3, - 57)

\frac{d}{d x} (e^{x} (2 x^{4} - 1))

\frac{d ^{2}}{d x ^{2}} (2 x)

What is the derivative of (x^2+6)^9 ?
The derivative of (x^2+6)^9 is 18x(x^2+6)^8
What is the first derivative of (x^2+6)^9 ?
The first derivative of (x^2+6)^9 is 18x(x^2+6)^8