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Popular >

xy^'-2y=0

Solution

x y^{^{'}} - 2 y = 0

Solution

y = c_{1} x^{2}

Solution steps

x y^{'} (x) - 2 y = 0

Solve separable ODE:

y = c_{1} x^{2}

y = c_{1} x^{2}

Graph

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\frac{\partial}{\partial x} (2 x^{\frac{1}{2}} y^{\frac{1}{4}})

Frequently Asked Questions (FAQ)

What is the solution for xy^'-2y=0 ?
The solution for xy^'-2y=0 is y=c_{1}x^2