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Popular >

y^'+y=4x

Solution

y^{^{'}} + y = 4 x

Solution

y = 4 (x - 1) + \frac{c _{1}}{e ^{x}}

Solution steps

y^{'} (x) + y = 4 x

Solve linear ODE:

y = 4 (x - 1) + \frac{c _{1}}{e ^{x}}

y = 4 (x - 1) + \frac{c _{1}}{e ^{x}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+y=4x ?
The solution for y^'+y=4x is y=4(x-1)+(c_{1})/(e^x)