What is the derivative of f(x)=x(x^2+1) ?

The derivative of f(x)=x(x^2+1) is 3x^2+1

What is the first derivative of f(x)=x(x^2+1) ?

The first derivative of f(x)=x(x^2+1) is 3x^2+1

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derivative of

f (x) = x (x^{2} + 1)

3 x^{2} + 1

Solution steps

\frac{d}{d x} (x (x^{2} + 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = x^{2} + 1

= \frac{d x}{d x} (x^{2} + 1) + \frac{d}{d x} (x^{2} + 1) x

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 1) = 2 x

= 1 \cdot (x^{2} + 1) + 2 xx

Simplify

1 \cdot (x^{2} + 1) + 2 xx : 3 x^{2} + 1

= 3 x^{2} + 1

(\frac{x}{x - 1})^{x}

y^{^{''}} + 4 y^{^{'}} - 45 y = 0

f (x) = 3.6 x + 500

\int \frac{1}{2 - e ^{3 x}} d x

\frac{d}{d x} ((x + 1) (x - 2)^{2})

What is the derivative of f(x)=x(x^2+1) ?
The derivative of f(x)=x(x^2+1) is 3x^2+1
What is the first derivative of f(x)=x(x^2+1) ?
The first derivative of f(x)=x(x^2+1) is 3x^2+1