What is the integral from 0 to 4 of 1/x ?

The integral from 0 to 4 of 1/x is diverges

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integral from 0 to 4 of 1/x

\int_{0}^{4} \frac{1}{x} d x

diverges

Solution steps

\int_{0}^{4} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{0}^{4}

Compute the boundaries:

diverges

= diverges

\frac{3}{8 x ^{\frac{5}{2}}}

\int (t^{2} - 2 t^{4}) d t

\int_{1}^{2} \frac{1}{x ^{5}} d x

\frac{\partial}{\partial x} (y e^{4 x})

\int_{1}^{5} \frac{ln ( x )}{x ^{7}} d x

What is the integral from 0 to 4 of 1/x ?
The integral from 0 to 4 of 1/x is diverges