What is the solution for x^3(dy)/(dx)+3x^2y=x ?

The solution for x^3(dy)/(dx)+3x^2y=x is y= 1/(2x)+(c_{1})/(x^3)

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x^3(dy)/(dx)+3x^2y=x

x^{3} \frac{d y}{d x} + 3 x^{2} y = x

y = \frac{1}{2 x} + \frac{c _{1}}{x ^{3}}

Solution steps

x^{3} \frac{d y}{d x} + 3 x^{2} y = x

Solve linear ODE:

y = \frac{1}{2 x} + \frac{c _{1}}{x ^{3}}

y = \frac{1}{2 x} + \frac{c _{1}}{x ^{3}}

(\frac{2}{5} x)^{3}

\frac{\partial}{\partial x} (- 2 x^{2} + 4 y^{2} + 3 z^{2} + 43)

\frac{\partial}{\partial y} (2 x + y e^{x})

\frac{d}{d x} (- 4 x^{3} + 10 x^{2} - x)

\frac{\partial}{\partial x} (\frac{2 x}{3 y})

What is the solution for x^3(dy)/(dx)+3x^2y=x ?
The solution for x^3(dy)/(dx)+3x^2y=x is y= 1/(2x)+(c_{1})/(x^3)