What is the limit as x approaches 1 of (2x^2)/(x-1) ?

The limit as x approaches 1 of (2x^2)/(x-1) is diverges

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limit as x approaches 1 of (2x^2)/(x-1)

x \to 1 lim (\frac{2 x ^{2}}{x - 1})

diverges

Solution steps

x \to 1 lim (\frac{2 x ^{2}}{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{2 x ^{2}}{x - 1}) = \infty

x \to 1 - lim (\frac{2 x ^{2}}{x - 1}) = - \infty

= diverges

\frac{d y}{d x} + 2 y = 3 x

y^{^{''}} - 10 y^{^{'}} + 26 y = 0

(1 + x) y^{^{'}} + y = x

\frac{\partial}{\partial x} (x^{2} sin (\frac{x}{y}))

\int_{0}^{1} 16 \frac{1}{x ^{p}} d x

What is the limit as x approaches 1 of (2x^2)/(x-1) ?
The limit as x approaches 1 of (2x^2)/(x-1) is diverges