What is (\partial)/(\partial x)(8x^2+y^2) ?

The answer to (\partial)/(\partial x)(8x^2+y^2) is 16x

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(\partial)/(\partial x)(8x^2+y^2)

\frac{\partial}{\partial x} (8 x^{2} + y^{2})

16 x

Solution steps

\frac{\partial}{\partial x} (8 x^{2} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (8 x^{2}) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (8 x^{2}) = 16 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 16 x + 0

Simplify

= 16 x

\frac{\partial}{\partial x} (e^{4 x yz - 7})

y = 3 ln (x), y = 0, x = 2 e

x^{2} y^{^{'}} + 2 x y = sin (4 x)

\int - 2 x 9 - x^{2} d x

\int \frac{1 + 4 p}{2 - 2 p - 4 p ^{2}} d p

What is (\partial)/(\partial x)(8x^2+y^2) ?
The answer to (\partial)/(\partial x)(8x^2+y^2) is 16x