What is (\partial)/(\partial x)(e^{4xyz-7}) ?

The answer to (\partial)/(\partial x)(e^{4xyz-7}) is e^{4xyz-7}*4yz

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(\partial)/(\partial x)(e^{4xyz-7})

\frac{\partial}{\partial x} (e^{4 x yz - 7})

e^{4 x yz - 7} \cdot 4 yz

Solution steps

\frac{\partial}{\partial x} (e^{4 x yz - 7})

Treat

y, z

as constants

Apply the chain rule:

e^{4 x yz - 7} \frac{\partial}{\partial x} (4 x yz - 7)

= e^{4 x yz - 7} \frac{\partial}{\partial x} (4 x yz - 7)

\frac{\partial}{\partial x} (4 x yz - 7) = 4 yz

= e^{4 x yz - 7} \cdot 4 yz

y = 3 ln (x), y = 0, x = 2 e

x^{2} y^{^{'}} + 2 x y = sin (4 x)

\int - 2 x 9 - x^{2} d x

\int \frac{1 + 4 p}{2 - 2 p - 4 p ^{2}} d p

\int_{0}^{4} (\frac{1}{4} x + (x + 1)) d x

What is (\partial)/(\partial x)(e^{4xyz-7}) ?
The answer to (\partial)/(\partial x)(e^{4xyz-7}) is e^{4xyz-7}*4yz