What is (\partial)/(\partial x)(2x+y^2) ?

The answer to (\partial)/(\partial x)(2x+y^2) is 2

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(\partial)/(\partial x)(2x+y^2)

\frac{\partial}{\partial x} (2 x + y^{2})

2

Solution steps

\frac{\partial}{\partial x} (2 x + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 + 0

Simplify

= 2

\frac{d}{d x} (arcsinh (tan (x)))

\frac{d}{d x} (8 + 3 x^{2})

\int ln (9 x + 4) d x

\frac{d}{d x} (\frac{1 - 2 x}{4 + x})

n = 0 \sum \infty 4 (\frac{2}{3})^{2 n}

What is (\partial)/(\partial x)(2x+y^2) ?
The answer to (\partial)/(\partial x)(2x+y^2) is 2