What is the derivative of f(x)= 1/2 x^2+7x ?

The derivative of f(x)= 1/2 x^2+7x is x+7

What is the first derivative of f(x)= 1/2 x^2+7x ?

The first derivative of f(x)= 1/2 x^2+7x is x+7

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derivative of

f (x) = \frac{1}{2} x^{2} + 7 x

x + 7

Solution steps

\frac{d}{d x} (\frac{1}{2} x^{2} + 7 x)

Simplify

\frac{1}{2} x^{2} + 7 x : \frac{x ^{2}}{2} + 7 x

= \frac{d}{d x} (\frac{x ^{2}}{2} + 7 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{2}}{2}) + \frac{d}{d x} (7 x)

\frac{d}{d x} (\frac{x ^{2}}{2}) = x

\frac{d}{d x} (7 x) = 7

= x + 7

\int co tan (x) d x

x \to \frac{π}{3} lim (x cos (x))

y^{^{'}} + 2 y = e^{2 x}

x \to 0 + lim (lo g_{3} (x))

\int (10 x^{4} - 2 sec^{2} (x)) d x

What is the derivative of f(x)= 1/2 x^2+7x ?
The derivative of f(x)= 1/2 x^2+7x is x+7
What is the first derivative of f(x)= 1/2 x^2+7x ?
The first derivative of f(x)= 1/2 x^2+7x is x+7