What is the limit as t approaches 0 of 7/(1+t) ?

The limit as t approaches 0 of 7/(1+t) is 7

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limit as t approaches 0 of 7/(1+t)

t \to 0 lim (\frac{7}{1 + t})

7

Solution steps

t \to 0 lim (\frac{7}{1 + t})

Plug in the value

t = 0

= \frac{7}{1 + 0}

Simplify

= 7

\frac{\partial}{\partial y} (arctan (x + 8 y))

\frac{d}{d x} (\frac{1 - 3 x}{4 + x})

y = 9 x^{2} e^{x}

n = 1 \sum \infty (- 5)^{- n}

\frac{d}{d x} (sin^{2} (x) + 2^{s i n (x)})

What is the limit as t approaches 0 of 7/(1+t) ?
The limit as t approaches 0 of 7/(1+t) is 7