What is the integral of-cos(x)+sin(x)+1 ?

The integral of-cos(x)+sin(x)+1 is -sin(x)-cos(x)+x+C

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integral of-cos(x)+sin(x)+1

\int - cos (x) + sin (x) + 1 d x

- sin (x) - cos (x) + x + C

Solution steps

\int - cos (x) + sin (x) + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int cos (x) d x + \int sin (x) d x + \int 1 d x

\int cos (x) d x = sin (x)

\int sin (x) d x = - cos (x)

\int 1 d x = x

= - sin (x) - cos (x) + x

Add a constant to the solution

= - sin (x) - cos (x) + x + C

n = 2 \sum \infty 5 (- \frac{1}{3})^{n}

\int \frac{5 x ^{2}}{2} d x

y = \frac{3 ln ( 4 x )}{5 - 2 x}

f (x) = - 3 x^{3} - 2 x, (- 1, 5)

x^{2} y^{^{'}} + y = 0

What is the integral of-cos(x)+sin(x)+1 ?
The integral of-cos(x)+sin(x)+1 is -sin(x)-cos(x)+x+C