What is the limit as x approaches 3+of 6/((x-3)^5) ?

The limit as x approaches 3+of 6/((x-3)^5) is infinity

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limit as x approaches 3+of 6/((x-3)^5)

x \to 3 + lim (\frac{6}{( x - 3 ) ^{5}})

\infty

Solution steps

x \to 3 + lim (\frac{6}{( x - 3 ) ^{5}})

For

x

approaching

3

from the right

, x > 3 \Rightarrow (x - 3)^{5} > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

y = \frac{4}{x ^{4}}

(x + 2)^{^{'}}

f (x) = (2 x^{3} + 3 x) (x - 3) (x + 5)

y^{^{''}} - 8 y^{^{'}} + 20 y = 100 x^{2} - 26 x e^{x}

\int - x + 2 d x

What is the limit as x approaches 3+of 6/((x-3)^5) ?
The limit as x approaches 3+of 6/((x-3)^5) is infinity