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Popular >

y'=y(5-y)

Solution

y^{^{'}} = y (5 - y)

Solution

y = \frac{5}{- e ^{- 5 t - c_{1}} + 1}

Solution steps

y^{'} (t) = y (5 - y)

Solve Bernoulli ODE:

y = \frac{5}{- e ^{- 5 t - c_{1}} + 1}

y = \frac{5}{- e ^{- 5 t - c_{1}} + 1}

Popular Examples

(\partial)/(\partial y)(-4e^xcos(yz))

\frac{\partial}{\partial y} (- 4 e^{x} cos (yz))

derivative of sqrt(1+x^2)+x^2sqrt(1+x^2)

\frac{d}{d x} (1 + x^{2} + x^{2} 1 + x^{2})

integral of (5e^{2x}+1/x)

\int (5 e^{2 x} + \frac{1}{x}) d x

derivative of sin(kt)

\frac{d}{d x} (sin (k t))

derivative of f(x)=(5+2x)e^{-3x}derivative of

f (x) = (5 + 2 x) e^{- 3 x}

Frequently Asked Questions (FAQ)

What is the solution for y'=y(5-y) ?
The solution for y'=y(5-y) is y= 5/(-e^{-5t-c_{1)}+1}