What is the derivative of (0.4x+2)(0.5x-5) ?

The derivative of (0.4x+2)(0.5x-5) is 0.4x-1

What is the first derivative of (0.4x+2)(0.5x-5) ?

The first derivative of (0.4x+2)(0.5x-5) is 0.4x-1

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derivative of

(0.4 x + 2) (0.5 x - 5)

0.4 x - 1

Solution steps

\frac{d}{d x} ((0.4 x + 2) (0.5 x - 5))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 0.4 x + 2, g = 0.5 x - 5

= \frac{d}{d x} (0.4 x + 2) (0.5 x - 5) + \frac{d}{d x} (0.5 x - 5) (0.4 x + 2)

\frac{d}{d x} (0.4 x + 2) = 0.4

\frac{d}{d x} (0.5 x - 5) = 0.5

= 0.4 (0.5 x - 5) + 0.5 (0.4 x + 2)

Simplify

0.4 (0.5 x - 5) + 0.5 (0.4 x + 2) : 0.4 x - 1

= 0.4 x - 1

\frac{d}{d x} (x^{7} e^{10 x})

\frac{d}{d x} ((x - 2)^{4})

y^{^{''}} - 30 y^{^{'}} + 225 y = 0

y \to \frac{1}{2} lim ((16 y^{2} - 4)^{4})

x \to o lim (x^{x})

What is the derivative of (0.4x+2)(0.5x-5) ?
The derivative of (0.4x+2)(0.5x-5) is 0.4x-1
What is the first derivative of (0.4x+2)(0.5x-5) ?
The first derivative of (0.4x+2)(0.5x-5) is 0.4x-1