What is the derivative of (x-2^4) ?

The derivative of (x-2^4) is 4(x-2)^3

What is the first derivative of (x-2^4) ?

The first derivative of (x-2^4) is 4(x-2)^3

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\frac{d}{d x} ((x - 2)^{4})

4 (x - 2)^{3}

Solution steps

\frac{d}{d x} ((x - 2)^{4})

Apply the chain rule:

4 (x - 2)^{3} \frac{d}{d x} (x - 2)

= 4 (x - 2)^{3} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= 4 (x - 2)^{3} \cdot 1

Simplify

= 4 (x - 2)^{3}

y^{^{''}} - 30 y^{^{'}} + 225 y = 0

y \to \frac{1}{2} lim ((16 y^{2} - 4)^{4})

x \to o lim (x^{x})

\frac{d}{d y} (2 x y^{4} e^{y})

f (x) 6 x^{4} - 10 x^{3} - 5 x^{2} + 16 x - 45

What is the derivative of (x-2^4) ?
The derivative of (x-2^4) is 4(x-2)^3
What is the first derivative of (x-2^4) ?
The first derivative of (x-2^4) is 4(x-2)^3