What is the derivative of f(x)6x^4-10x^3-5x^2+16x-45 ?

The derivative of f(x)6x^4-10x^3-5x^2+16x-45 is 6x^5

What is the first derivative of f(x)6x^4-10x^3-5x^2+16x-45 ?

The first derivative of f(x)6x^4-10x^3-5x^2+16x-45 is 6x^5

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derivative of

f (x) 6 x^{4} - 10 x^{3} - 5 x^{2} + 16 x - 45

6 x^{5}

Solution steps

\frac{d}{df} (f x \cdot 6 x^{4} - 10 x^{3} - 5 x^{2} + 16 x - 45)

Simplify

f x \cdot 6 x^{4} - 10 x^{3} - 5 x^{2} + 16 x - 45 : 6 f x^{5} - 10 x^{3} - 5 x^{2} + 16 x - 45

= \frac{d}{df} (6 f x^{5} - 10 x^{3} - 5 x^{2} + 16 x - 45)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{df} (6 f x^{5}) - \frac{d}{df} (10 x^{3}) - \frac{d}{df} (5 x^{2}) + \frac{d}{df} (16 x) - \frac{d}{df} (45)

\frac{d}{df} (6 f x^{5}) = 6 x^{5}

\frac{d}{df} (10 x^{3}) = 0

\frac{d}{df} (5 x^{2}) = 0

\frac{d}{df} (16 x) = 0

\frac{d}{df} (45) = 0

= 6 x^{5} - 0 - 0 + 0 - 0

Simplify

= 6 x^{5}

f (x) = \frac{2}{3 x + 1}, at x = - 1

x \to \frac{π}{3} lim (7 x cos (x))

\frac{d}{d x} (\frac{7}{4 x + 1})

y = e^{3 - x}

y + (x^{2} + y^{2}) d x - x d y = 0

What is the derivative of f(x)6x^4-10x^3-5x^2+16x-45 ?
The derivative of f(x)6x^4-10x^3-5x^2+16x-45 is 6x^5
What is the first derivative of f(x)6x^4-10x^3-5x^2+16x-45 ?
The first derivative of f(x)6x^4-10x^3-5x^2+16x-45 is 6x^5