What is the derivative of 3x-4x^{7/8} ?

The derivative of 3x-4x^{7/8} is 3-7/(2x^{1/8)}

What is the first derivative of 3x-4x^{7/8} ?

The first derivative of 3x-4x^{7/8} is 3-7/(2x^{1/8)}

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\frac{d}{d x} (3 x - 4 x^{\frac{7}{8}})

3 - \frac{7}{2 x ^{\frac{1}{8}}}

Solution steps

\frac{d}{d x} (3 x - 4 x^{\frac{7}{8}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (4 x^{\frac{7}{8}})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4 x^{\frac{7}{8}}) = \frac{7}{2 x ^{\frac{1}{8}}}

= 3 - \frac{7}{2 x ^{\frac{1}{8}}}

x \to 0 lim (\frac{( 4 e ^{x} - 4 )}{x})

\frac{d}{d x} (sin (2 x^{2} \cdot e^{- x}))

f (x) = (x - 2) (2 x + 3), at x = 0

\int (x - 5) \cdot sin (x) d x

\int \frac{sin ( x ) tan ( x )}{9 + sec ^{2} ( x )} d x

What is the derivative of 3x-4x^{7/8} ?
The derivative of 3x-4x^{7/8} is 3-7/(2x^{1/8)}
What is the first derivative of 3x-4x^{7/8} ?
The first derivative of 3x-4x^{7/8} is 3-7/(2x^{1/8)}