What is the limit as x approaches 0 of (cos(5x)-1)/(sin(9x)) ?

The limit as x approaches 0 of (cos(5x)-1)/(sin(9x)) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (cos(5x)-1)/(sin(9x))

x \to 0 lim (\frac{cos ( 5 x ) - 1}{sin ( 9 x )})

0

Solution steps

x \to 0 lim (\frac{cos ( 5 x ) - 1}{sin ( 9 x )})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{- 5 sin ( 5 x )}{cos ( 9 x ) \cdot 9})

= x \to 0 lim (\frac{- 5 sin ( 5 x )}{cos ( 9 x ) \cdot 9})

Plug in the value

x = 0

= \frac{- 5 sin ( 5 \cdot 0 )}{cos ( 9 \cdot 0 ) \cdot 9}

Simplify

\frac{- 5 sin ( 5 \cdot 0 )}{cos ( 9 \cdot 0 ) \cdot 9} : 0

= 0

\frac{d y}{d x} = \frac{2 - e ^{x}}{3 + 2 y}

(8 x + 7)^{2}

n = 1 \sum \infty \frac{ln ( n )}{8 n}

\int x^{2} x^{3} + 8 d x

\frac{d}{d x} (\frac{300}{3 + 17 e ^{- 0.0625 x}})

What is the limit as x approaches 0 of (cos(5x)-1)/(sin(9x)) ?
The limit as x approaches 0 of (cos(5x)-1)/(sin(9x)) is 0